Stimulus Current \(I_{stim}\)= mA
Stimulation
$$C_m\frac{dV}{dt}=I_{Na}+I_{K}+I_L+I_{stim}$$ $$I_{Na}=\bar{g}_{Na}m^3h\left ( E_{Na} - V \right )$$ $$I_{K}=\bar{g}_{K}n^4\left ( E_{K} - V \right )$$ $$I_{L}=\bar{g}_{L}\left( E_{L} - V \right )$$
and
$$\frac{dm}{dt}=\alpha_m\left ( V \right )\left ( 1-m \right )-\beta_m\left ( V \right )m$$ $$\frac{dh}{dt}=\alpha_h\left ( V \right )\left ( 1-h \right )-\beta_h\left ( V \right )h$$ $$\frac{dn}{dt}=\alpha_n\left ( V \right )\left ( 1-n \right )-\beta_n\left ( V \right )n$$
$$\alpha_m\left ( V \right )=\frac{0.1\left ( V+40 \right )}{1-\exp\left ( -\left ( V+40 \right )/10 \right )}$$ $$\beta_m\left ( V \right )=4\exp\left ( -\left ( V+65 \right )/18 \right )$$ $$\alpha_h\left ( V \right )=0.07\exp\left ( -\left ( V+65 \right )/20 \right )$$ $$\beta_h\left ( V \right )=\frac{1}{1-\exp\left ( -\left ( V+35 \right )/10 \right )}$$ $$\alpha_n\left ( V \right )=\frac{0.01\left ( V+55 \right )}{1-\exp\left ( -\left ( V+55 \right )/10 \right )}$$ $$\beta_n\left ( V \right )=0.125\exp\left ( -\left ( V+65 \right )/80 \right )$$ Parameters
\(C_m=\) 0 \(\mu F/cm^2\)
\(\bar{g}_{Na}=\) 0 \(mS/cm^3\)
\(\bar{g}_{K}=\) 0 \(mS/cm^3\)
\(\bar{g}_{L}=\) 0 \(mS/cm^3\)
\(E_{Na}=\) 0 \(mV\)
\(E_{K}=\) 0 \(mV\)
\(E_{L}=\) 0 \(mV\)