Ch. 5 Homework, Phy 131, Fall 1997, Tulane

5.1   0.42

5.4   0.23

5.9   (a) kg/s      (b) kg/m

5.15  (a) a = 2.45 m/s^2    T = 37 N
      (b) a = g [m2 - m1 sin(theta)]/[m1+m2]
          T = g m1 m2 [1+ sin(theta)]/[m1+m2]

5.19  (a) In the boxcar, the object would appear to have a negative 
          acceleration. Thus it will slow down and go backward.
      (b) 4 s

5.27  84 m

5.43  (a) a = 2 m/s^2     Fc = 8 N
      (b) Fc = F m2 / [m1+m2]

5.50  (a) g = 2 L (m1+m2)/(m1-m2)/t^2
      (c) dg/g = 2 |dt/t| = 5%,   t = 4s
          Thus m2 = 0.926 kg